3m^2+72m=0

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Solution for 3m^2+72m=0 equation: 



3m^2+72m=0

a = 3; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·3·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*3}=\frac{-144}{6}
=-24
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*3}=\frac{0}{6}
=0
$

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